(5x-3)(6x+6)=0

Solution for (5x-3)(6x+6)=0 equation:

(5x-3)(6x+6)=0

We multiply parentheses ..

(+30x^2+30x-18x-18)=0

We get rid of parentheses

30x^2+30x-18x-18=0

We add all the numbers together, and all the variables

30x^2+12x-18=0

a = 30; b = 12; c = -18;
Δ = b2-4ac
Δ = 122-4·30·(-18)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-48}{2*30}=\frac{-60}{60}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+48}{2*30}=\frac{36}{60}
=3/5
$