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(5x-3)(7x-3)=0
We multiply parentheses ..
(+35x^2-15x-21x+9)=0
We get rid of parentheses
35x^2-15x-21x+9=0
We add all the numbers together, and all the variables
35x^2-36x+9=0
a = 35; b = -36; c = +9;
Δ = b2-4ac
Δ = -362-4·35·9
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-6}{2*35}=\frac{30}{70} =3/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+6}{2*35}=\frac{42}{70} =3/5 $
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