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(5x-3)(8x-9)=131
We move all terms to the left:
(5x-3)(8x-9)-(131)=0
We multiply parentheses ..
(+40x^2-45x-24x+27)-131=0
We get rid of parentheses
40x^2-45x-24x+27-131=0
We add all the numbers together, and all the variables
40x^2-69x-104=0
a = 40; b = -69; c = -104;
Δ = b2-4ac
Δ = -692-4·40·(-104)
Δ = 21401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-69)-\sqrt{21401}}{2*40}=\frac{69-\sqrt{21401}}{80} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-69)+\sqrt{21401}}{2*40}=\frac{69+\sqrt{21401}}{80} $
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