(5x-3)+(6x+1)=5(3x+2)

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Solution for (5x-3)+(6x+1)=5(3x+2) equation: 



(5x-3)+(6x+1)=5(3x+2)

We move all terms to the left:

(5x-3)+(6x+1)-(5(3x+2))=0

We get rid of parentheses

5x+6x-(5(3x+2))-3+1=0



We calculate terms in parentheses: -(5(3x+2)), so:

5(3x+2)

We multiply parentheses

15x+10

Back to the equation:

-(15x+10)



We add all the numbers together, and all the variables

11x-(15x+10)-2=0

We get rid of parentheses

11x-15x-10-2=0

We add all the numbers together, and all the variables

-4x-12=0

We move all terms containing x to the left, all other terms to the right

-4x=12

x=12/-4

x=-3

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