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(5x-3)-(2x-4)=-(x+3)-(x+5)-(x+3)
We move all terms to the left:
(5x-3)-(2x-4)-(-(x+3)-(x+5)-(x+3))=0
We get rid of parentheses
5x-2x-(-(x+3)-(x+5)-(x+3))-3+4=0
We calculate terms in parentheses: -(-(x+3)-(x+5)-(x+3)), so:We add all the numbers together, and all the variables
-(x+3)-(x+5)-(x+3)
We get rid of parentheses
-x-x-x-3-5-3
We add all the numbers together, and all the variables
-3x-11
Back to the equation:
-(-3x-11)
3x-(-3x-11)+1=0
We get rid of parentheses
3x+3x+11+1=0
We add all the numbers together, and all the variables
6x+12=0
We move all terms containing x to the left, all other terms to the right
6x=-12
x=-12/6
x=-2
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