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(5x-3)/(2x+1)=11
We move all terms to the left:
(5x-3)/(2x+1)-(11)=0
Domain of the equation: (2x+1)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
2x!=-1
x!=-1/2
x!=-1/2
x∈R
(5x-3)-11*(2x+1)=0
We multiply parentheses
(5x-3)-22x-11=0
We get rid of parentheses
5x-22x-3-11=0
We add all the numbers together, and all the variables
-17x-14=0
We move all terms containing x to the left, all other terms to the right
-17x=14
x=14/-17
x=-14/17
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