(5x-3)/20=(2x+1)/5

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Solution for (5x-3)/20=(2x+1)/5 equation: 



(5x-3)/20=(2x+1)/5

We move all terms to the left:

(5x-3)/20-((2x+1)/5)=0

We calculate fractions


5x/()+(-((2x+1)*20)/()=0



We calculate terms in parentheses: +(-((2x+1)*20)/(), so:

-((2x+1)*20)/(

We multiply all the terms by the denominator


-((2x+1)*20)



We calculate terms in parentheses: -((2x+1)*20), so:

(2x+1)*20

We multiply parentheses

40x+20

Back to the equation:

-(40x+20)



We get rid of parentheses

-40x-20

Back to the equation:

+(-40x-20)



We get rid of parentheses

5x/()-40x-20=0

We multiply all the terms by the denominator


5x-40x*()-20*()=0

We add all the numbers together, and all the variables

5x-40x*()=0

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