(5x-32)=(7/x+3)-(3x)

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Solution for (5x-32)=(7/x+3)-(3x) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5*x-32 = 7/x-(3*x)+3 // - 7/x-(3*x)+3

5*x+3*x-(7/x)-32-3 = 0

5*x+3*x-7*x^-1-32-3 = 0

8*x^1-7*x^-1-35*x^0 = 0

(8*x^2-35*x^1-7*x^0)/(x^1) = 0 // * x^2

x^1*(8*x^2-35*x^1-7*x^0) = 0

x^1

8*x^2-35*x-7 = 0

8*x^2-35*x-7 = 0

DELTA = (-35)^2-(-7*4*8)

DELTA = 1449

DELTA > 0

x = (1449^(1/2)+35)/(2*8) or x = (35-1449^(1/2))/(2*8)

x = (3*161^(1/2)+35)/16 or x = (35-3*161^(1/2))/16

x in { (35-3*161^(1/2))/16, (3*161^(1/2)+35)/16}

x in { (35-3*161^(1/2))/16, (3*161^(1/2)+35)/16 }

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