(5x-32/x-4)=(7/x+3)-(3x/x-4)

Solution for (5x-32/x-4)=(7/x+3)-(3x/x-4) equation:

D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5*x-(32/x)-4 = 7/x-((3*x)/x)+3+4 // - 7/x-((3*x)/x)+3+4

5*x-(32/x)-(7/x)+(3*x)/x-4-4-3 = 0

5*x-32*x^-1-7*x^-1+(3*x)/x-4-4-3 = 0

5*x^1-39*x^-1-8*x^0 = 0

(5*x^2-8*x^1-39*x^0)/(x^1) = 0 // * x^2

x^1*(5*x^2-8*x^1-39*x^0) = 0

x^1

5*x^2-8*x-39 = 0

5*x^2-8*x-39 = 0

DELTA = (-8)^2-(-39*4*5)

DELTA = 844

DELTA > 0

x = (844^(1/2)+8)/(2*5) or x = (8-844^(1/2))/(2*5)

x = (2*211^(1/2)+8)/10 or x = (8-2*211^(1/2))/10

x in { (8-2*211^(1/2))/10, (2*211^(1/2)+8)/10} 

x in { (8-2*211^(1/2))/10, (2*211^(1/2)+8)/10 }