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(5x-4)(4x+7)=0
We multiply parentheses ..
(+20x^2+35x-16x-28)=0
We get rid of parentheses
20x^2+35x-16x-28=0
We add all the numbers together, and all the variables
20x^2+19x-28=0
a = 20; b = 19; c = -28;
Δ = b2-4ac
Δ = 192-4·20·(-28)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-51}{2*20}=\frac{-70}{40} =-1+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+51}{2*20}=\frac{32}{40} =4/5 $
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