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(5x-4)(4x-2)=180
We move all terms to the left:
(5x-4)(4x-2)-(180)=0
We multiply parentheses ..
(+20x^2-10x-16x+8)-180=0
We get rid of parentheses
20x^2-10x-16x+8-180=0
We add all the numbers together, and all the variables
20x^2-26x-172=0
a = 20; b = -26; c = -172;
Δ = b2-4ac
Δ = -262-4·20·(-172)
Δ = 14436
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14436}=\sqrt{36*401}=\sqrt{36}*\sqrt{401}=6\sqrt{401}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-6\sqrt{401}}{2*20}=\frac{26-6\sqrt{401}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+6\sqrt{401}}{2*20}=\frac{26+6\sqrt{401}}{40} $
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