(5x-4)(5-4x)=25x-20x2-20+16x=

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Solution for (5x-4)(5-4x)=25x-20x2-20+16x= equation:



(5x-4)(5-4x)=25x-20x^2-20+16x=
We move all terms to the left:
(5x-4)(5-4x)-(25x-20x^2-20+16x)=0
We add all the numbers together, and all the variables
-(25x-20x^2-20+16x)+(5x-4)(-4x+5)=0
We get rid of parentheses
20x^2-25x-16x+(5x-4)(-4x+5)+20=0
We multiply parentheses ..
20x^2+(-20x^2+25x+16x-20)-25x-16x+20=0
We add all the numbers together, and all the variables
20x^2+(-20x^2+25x+16x-20)-41x+20=0
We get rid of parentheses
20x^2-20x^2+25x+16x-41x-20+20=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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