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(5x-4)(x-1)=0
We multiply parentheses ..
(+5x^2-5x-4x+4)=0
We get rid of parentheses
5x^2-5x-4x+4=0
We add all the numbers together, and all the variables
5x^2-9x+4=0
a = 5; b = -9; c = +4;
Δ = b2-4ac
Δ = -92-4·5·4
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-1}{2*5}=\frac{8}{10} =4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+1}{2*5}=\frac{10}{10} =1 $
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