(5x-4)*3-(4-3x)*5=7x+(3x-9)*7

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Solution for (5x-4)*3-(4-3x)*5=7x+(3x-9)*7 equation: 



(5x-4)*3-(4-3x)*5=7x+(3x-9)*7

We move all terms to the left:

(5x-4)*3-(4-3x)*5-(7x+(3x-9)*7)=0

We add all the numbers together, and all the variables

(5x-4)*3-(-3x+4)*5-(7x+(3x-9)*7)=0

We multiply parentheses

15x+15x-(7x+(3x-9)*7)-12-20=0



We calculate terms in parentheses: -(7x+(3x-9)*7), so:

7x+(3x-9)*7

We multiply parentheses

7x+21x-63

We add all the numbers together, and all the variables

28x-63

Back to the equation:

-(28x-63)



We add all the numbers together, and all the variables

30x-(28x-63)-32=0

We get rid of parentheses

30x-28x+63-32=0

We add all the numbers together, and all the variables

2x+31=0

We move all terms containing x to the left, all other terms to the right

2x=-31

x=-31/2

x=-15+1/2

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