(5x-4)+(4x-2)=0

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Solution for (5x-4)+(4x-2)=0 equation: 



(5x-4)+(4x-2)=0

We get rid of parentheses

5x+4x-4-2=0

We add all the numbers together, and all the variables

9x-6=0

We move all terms containing x to the left, all other terms to the right

9x=6

x=6/9

x=2/3

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