(5x-4)-8x=(7+5x)-5

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Solution for (5x-4)-8x=(7+5x)-5 equation: 



(5x-4)-8x=(7+5x)-5

We move all terms to the left:

(5x-4)-8x-((7+5x)-5)=0

We add all the numbers together, and all the variables

(5x-4)-8x-((5x+7)-5)=0

We add all the numbers together, and all the variables

-8x+(5x-4)-((5x+7)-5)=0

We get rid of parentheses

-8x+5x-((5x+7)-5)-4=0



We calculate terms in parentheses: -((5x+7)-5), so:

(5x+7)-5

We get rid of parentheses

5x+7-5

We add all the numbers together, and all the variables

5x+2

Back to the equation:

-(5x+2)



We add all the numbers together, and all the variables

-3x-(5x+2)-4=0

We get rid of parentheses

-3x-5x-2-4=0

We add all the numbers together, and all the variables

-8x-6=0

We move all terms containing x to the left, all other terms to the right

-8x=6

x=6/-8

x=-3/4

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