(5x-4)/(2x-3)=10(3-x)/(17-4x)

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Solution for (5x-4)/(2x-3)=10(3-x)/(17-4x) equation: 


D( x )

2*x-3 = 0

17-(4*x) = 0

2*x-3 = 0

2*x-3 = 0

2*x-3 = 0 // + 3

2*x = 3 // : 2

x = 3/2

17-(4*x) = 0

17-(4*x) = 0

17-4*x = 0

17-4*x = 0 // - 17

-4*x = -17 // : -4

x = -17/(-4)

x = 17/4

x in (-oo:3/2) U (3/2:17/4) U (17/4:+oo)

(5*x-4)/(2*x-3) = (10*(3-x))/(17-(4*x)) // - (10*(3-x))/(17-(4*x))

(5*x-4)/(2*x-3)-((10*(3-x))/(17-(4*x))) = 0

(5*x-4)/(2*x-3)-10*(17-4*x)^-1*(3-x) = 0

(5*x-4)/(2*x-3)+(-10*(3-x))/(17-4*x) = 0

((5*x-4)*(17-4*x))/((2*x-3)*(17-4*x))+(-10*(3-x)*(2*x-3))/((2*x-3)*(17-4*x)) = 0

(5*x-4)*(17-4*x)-10*(3-x)*(2*x-3) = 0

11*x+22 = 0

(11*x+22)/((2*x-3)*(17-4*x)) = 0

(11*x+22)/((2*x-3)*(17-4*x)) = 0 // * (2*x-3)*(17-4*x)

11*x+22 = 0

11*x+22 = 0 // - 22

11*x = -22 // : 11

x = -22/11

x = -2

x = -2

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