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(5x-4)/(5x+4)=(2)/(3)
We move all terms to the left:
(5x-4)/(5x+4)-((2)/(3))=0
Domain of the equation: (5x+4)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
5x!=-4
x!=-4/5
x!=-4/5
x∈R
(5x-4)/(5x+4)-(+2/3)=0
We get rid of parentheses
(5x-4)/(5x+4)-2/3=0
We calculate fractions
(15x-12)/(15x+12)+(-10x-8)/(15x+12)=0
We multiply all the terms by the denominator
(15x-12)+(-10x-8)=0
We get rid of parentheses
15x-10x-12-8=0
We add all the numbers together, and all the variables
5x-20=0
We move all terms containing x to the left, all other terms to the right
5x=20
x=20/5
x=4
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