(5x-4)/6=4x+1-(3x+10)/2

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Solution for (5x-4)/6=4x+1-(3x+10)/2 equation: 



(5x-4)/6=4x+1-(3x+10)/2

We move all terms to the left:

(5x-4)/6-(4x+1-(3x+10)/2)=0

We calculate fractions


5x/()+(-(4x+1-(3x+10)*6)/()=0



We calculate terms in parentheses: +(-(4x+1-(3x+10)*6)/(), so:

-(4x+1-(3x+10)*6)/(

We multiply all the terms by the denominator


-(4x+1-(3x+10)*6)



We calculate terms in parentheses: -(4x+1-(3x+10)*6), so:

4x+1-(3x+10)*6

determiningTheFunctionDomain
4x-(3x+10)*6+1

We multiply parentheses

4x-18x-60+1

We add all the numbers together, and all the variables

-14x-59

Back to the equation:

-(-14x-59)



We get rid of parentheses

14x+59

Back to the equation:

+(14x+59)



We get rid of parentheses

5x/()+14x+59=0

We multiply all the terms by the denominator


5x+14x*()+59*()=0

We add all the numbers together, and all the variables

5x+14x*()=0

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