(5x-4)/8-(x-3)/4=(x+6)/4

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Solution for (5x-4)/8-(x-3)/4=(x+6)/4 equation: 



(5x-4)/8-(x-3)/4=(x+6)/4

We move all terms to the left:

(5x-4)/8-(x-3)/4-((x+6)/4)=0

We calculate fractions


5x/()+(-8x+24)/()+(-((x+6)*8)/()=0



We calculate terms in parentheses: +(-((x+6)*8)/(), so:

-((x+6)*8)/(

We multiply all the terms by the denominator


-((x+6)*8)



We calculate terms in parentheses: -((x+6)*8), so:

(x+6)*8

We multiply parentheses

8x+48

Back to the equation:

-(8x+48)



We get rid of parentheses

-8x-48

Back to the equation:

+(-8x-48)



We get rid of parentheses

5x/()+(-8x+24)/()-8x-48=0

We multiply all the terms by the denominator


5x+(-8x+24)-8x*()-48*()=0

We add all the numbers together, and all the variables

5x+(-8x+24)-8x*()=0

We get rid of parentheses

5x-8x-8x*()+24=0

We add all the numbers together, and all the variables

-3x-8x*()+24=0

We move all terms containing x to the left, all other terms to the right

-3x-8x*()=-24

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