If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(5x-40)=(2x+2)
We move all terms to the left:
(5x-40)-((2x+2))=0
We get rid of parentheses
5x-((2x+2))-40=0
We calculate terms in parentheses: -((2x+2)), so:We get rid of parentheses
(2x+2)
We get rid of parentheses
2x+2
Back to the equation:
-(2x+2)
5x-2x-2-40=0
We add all the numbers together, and all the variables
3x-42=0
We move all terms containing x to the left, all other terms to the right
3x=42
x=42/3
x=14
| 63=3*5x+3 | | 1/2(8x-16)=2/3(6x+12) | | 5^2-3x=7x | | d^2-13=0 | | 6-(4y-9)=7-5y | | 72y=8 | | 8+x-5=2(3x-8) | | −34y=−6−34y=−6 | | 2u-1/3-5u+9/6=-2 | | -2=x/5 | | 3(5x+8)=-44+8 | | 6(x-9)=5x-7 | | 2x+3(9x+12)=130 | | 3s-10=250 | | |x+12|=18 | | 1-7×b=20 | | X-6(2-x)=-48 | | (3x-1)=47 | | 7x+9-3x=1+3x+5 | | (7u-9)/5=2u | | 3x+(-2)=-14 | | -24+6y=42 | | -6=v/5+4 | | (5u-6)(3+u)=0 | | 13j–5j=16 | | 2.14x-12.18=-5.76, | | 5r+9=3r+22 | | -4t-1=3t+1-7t | | 32-(8x+17)+2=4(x+5) | | 1/7(h-1)=6h+4+2h | | 11=1.5x+5 | | 7x+5=66 |