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(5x-4=4x-2)
We move all terms to the left:
(5x-4-(4x-2))=0
We calculate terms in parentheses: +(5x-4-(4x-2)), so:We get rid of parentheses
5x-4-(4x-2)
determiningTheFunctionDomain 5x-(4x-2)-4
We get rid of parentheses
5x-4x+2-4
We add all the numbers together, and all the variables
x-2
Back to the equation:
+(x-2)
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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