(5x-4y)(5x+4y)=0

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Solution for (5x-4y)(5x+4y)=0 equation: 


Simplifying
(5x + -4y)(5x + 4y) = 0

Multiply (5x + -4y) * (5x + 4y)
(5x * (5x + 4y) + -4y * (5x + 4y)) = 0
((5x * 5x + 4y * 5x) + -4y * (5x + 4y)) = 0

Reorder the terms:
((20xy + 25x2) + -4y * (5x + 4y)) = 0
((20xy + 25x2) + -4y * (5x + 4y)) = 0
(20xy + 25x2 + (5x * -4y + 4y * -4y)) = 0
(20xy + 25x2 + (-20xy + -16y2)) = 0

Reorder the terms:
(20xy + -20xy + 25x2 + -16y2) = 0

Combine like terms: 20xy + -20xy = 0
(0 + 25x2 + -16y2) = 0
(25x2 + -16y2) = 0

Solving
25x2 + -16y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '16y2' to each side of the equation.
25x2 + -16y2 + 16y2 = 0 + 16y2

Combine like terms: -16y2 + 16y2 = 0
25x2 + 0 = 0 + 16y2
25x2 = 0 + 16y2
Remove the zero:
25x2 = 16y2

Divide each side by '25'.
x2 = 0.64y2

Simplifying
x2 = 0.64y2

Take the square root of each side:
x = {-0.8y, 0.8y}

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