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(5x-5)(2x+8)=0
We multiply parentheses ..
(+10x^2+40x-10x-40)=0
We get rid of parentheses
10x^2+40x-10x-40=0
We add all the numbers together, and all the variables
10x^2+30x-40=0
a = 10; b = 30; c = -40;
Δ = b2-4ac
Δ = 302-4·10·(-40)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-50}{2*10}=\frac{-80}{20} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+50}{2*10}=\frac{20}{20} =1 $
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