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(5x-5)(9x+17)=180
We move all terms to the left:
(5x-5)(9x+17)-(180)=0
We multiply parentheses ..
(+45x^2+85x-45x-85)-180=0
We get rid of parentheses
45x^2+85x-45x-85-180=0
We add all the numbers together, and all the variables
45x^2+40x-265=0
a = 45; b = 40; c = -265;
Δ = b2-4ac
Δ = 402-4·45·(-265)
Δ = 49300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{49300}=\sqrt{100*493}=\sqrt{100}*\sqrt{493}=10\sqrt{493}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-10\sqrt{493}}{2*45}=\frac{-40-10\sqrt{493}}{90} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+10\sqrt{493}}{2*45}=\frac{-40+10\sqrt{493}}{90} $
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