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(5x-5)+10x=2(-5x-40)
We move all terms to the left:
(5x-5)+10x-(2(-5x-40))=0
We add all the numbers together, and all the variables
10x+(5x-5)-(2(-5x-40))=0
We get rid of parentheses
10x+5x-(2(-5x-40))-5=0
We calculate terms in parentheses: -(2(-5x-40)), so:We add all the numbers together, and all the variables
2(-5x-40)
We multiply parentheses
-10x-80
Back to the equation:
-(-10x-80)
15x-(-10x-80)-5=0
We get rid of parentheses
15x+10x+80-5=0
We add all the numbers together, and all the variables
25x+75=0
We move all terms containing x to the left, all other terms to the right
25x=-75
x=-75/25
x=-3
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