(5x-50)+(2x)=(80-x)

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Solution for (5x-50)+(2x)=(80-x) equation: 



(5x-50)+(2x)=(80-x)

We move all terms to the left:

(5x-50)+(2x)-((80-x))=0

We add all the numbers together, and all the variables

(5x-50)+2x-((-1x+80))=0

We add all the numbers together, and all the variables

2x+(5x-50)-((-1x+80))=0

We get rid of parentheses

2x+5x-((-1x+80))-50=0



We calculate terms in parentheses: -((-1x+80)), so:

(-1x+80)

We get rid of parentheses

-1x+80

Back to the equation:

-(-1x+80)



We add all the numbers together, and all the variables

7x-(-1x+80)-50=0

We get rid of parentheses

7x+1x-80-50=0

We add all the numbers together, and all the variables

8x-130=0

We move all terms containing x to the left, all other terms to the right

8x=130

x=130/8

x=16+1/4

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