(5x-6)(7x+4)=0

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Solution for (5x-6)(7x+4)=0 equation:



(5x-6)(7x+4)=0
We multiply parentheses ..
(+35x^2+20x-42x-24)=0
We get rid of parentheses
35x^2+20x-42x-24=0
We add all the numbers together, and all the variables
35x^2-22x-24=0
a = 35; b = -22; c = -24;
Δ = b2-4ac
Δ = -222-4·35·(-24)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-62}{2*35}=\frac{-40}{70} =-4/7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+62}{2*35}=\frac{84}{70} =1+1/5 $

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