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(5x-6)(x+9)=0
We multiply parentheses ..
(+5x^2+45x-6x-54)=0
We get rid of parentheses
5x^2+45x-6x-54=0
We add all the numbers together, and all the variables
5x^2+39x-54=0
a = 5; b = 39; c = -54;
Δ = b2-4ac
Δ = 392-4·5·(-54)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-51}{2*5}=\frac{-90}{10} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+51}{2*5}=\frac{12}{10} =1+1/5 $
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