(5x-7)(-x+9)=0

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Solution for (5x-7)(-x+9)=0 equation:



(5x-7)(-x+9)=0
We add all the numbers together, and all the variables
(5x-7)(-1x+9)=0
We multiply parentheses ..
(-5x^2+45x+7x-63)=0
We get rid of parentheses
-5x^2+45x+7x-63=0
We add all the numbers together, and all the variables
-5x^2+52x-63=0
a = -5; b = 52; c = -63;
Δ = b2-4ac
Δ = 522-4·(-5)·(-63)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-38}{2*-5}=\frac{-90}{-10} =+9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+38}{2*-5}=\frac{-14}{-10} =1+2/5 $

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