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(5x-7)(3x+14)=0
We multiply parentheses ..
(+15x^2+70x-21x-98)=0
We get rid of parentheses
15x^2+70x-21x-98=0
We add all the numbers together, and all the variables
15x^2+49x-98=0
a = 15; b = 49; c = -98;
Δ = b2-4ac
Δ = 492-4·15·(-98)
Δ = 8281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8281}=91$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-91}{2*15}=\frac{-140}{30} =-4+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+91}{2*15}=\frac{42}{30} =1+2/5 $
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