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(5x-7)(6x+6)=0
We multiply parentheses ..
(+30x^2+30x-42x-42)=0
We get rid of parentheses
30x^2+30x-42x-42=0
We add all the numbers together, and all the variables
30x^2-12x-42=0
a = 30; b = -12; c = -42;
Δ = b2-4ac
Δ = -122-4·30·(-42)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-72}{2*30}=\frac{-60}{60} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+72}{2*30}=\frac{84}{60} =1+2/5 $
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