(5x-7)+(2x+2)=(10x-41)

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Solution for (5x-7)+(2x+2)=(10x-41) equation: 



(5x-7)+(2x+2)=(10x-41)

We move all terms to the left:

(5x-7)+(2x+2)-((10x-41))=0

We get rid of parentheses

5x+2x-((10x-41))-7+2=0



We calculate terms in parentheses: -((10x-41)), so:

(10x-41)

We get rid of parentheses

10x-41

Back to the equation:

-(10x-41)



We add all the numbers together, and all the variables

7x-(10x-41)-5=0

We get rid of parentheses

7x-10x+41-5=0

We add all the numbers together, and all the variables

-3x+36=0

We move all terms containing x to the left, all other terms to the right

-3x=-36

x=-36/-3

x=+12

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