(5x-7)+(4x-10)=(32)+(9x+3)

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Solution for (5x-7)+(4x-10)=(32)+(9x+3) equation: 



(5x-7)+(4x-10)=(32)+(9x+3)

We move all terms to the left:

(5x-7)+(4x-10)-((32)+(9x+3))=0

We get rid of parentheses

5x+4x-(32+(9x+3))-7-10=0



We calculate terms in parentheses: -(32+(9x+3)), so:

32+(9x+3)

determiningTheFunctionDomain
(9x+3)+32

We get rid of parentheses

9x+3+32

We add all the numbers together, and all the variables

9x+35

Back to the equation:

-(9x+35)



We add all the numbers together, and all the variables

9x-(9x+35)-17=0

We get rid of parentheses

9x-9x-35-17=0

We add all the numbers together, and all the variables

-52!=0

There is no solution for this equation

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