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(5x-7)/(3x+1)=-2/3
We move all terms to the left:
(5x-7)/(3x+1)-(-2/3)=0
Domain of the equation: (3x+1)!=0We get rid of parentheses
We move all terms containing x to the left, all other terms to the right
3x!=-1
x!=-1/3
x!=-1/3
x∈R
(5x-7)/(3x+1)+2/3=0
We calculate fractions
(15x-21)/(9x+3)+(6x+2)/(9x+3)=0
We multiply all the terms by the denominator
(15x-21)+(6x+2)=0
We get rid of parentheses
15x+6x-21+2=0
We add all the numbers together, and all the variables
21x-19=0
We move all terms containing x to the left, all other terms to the right
21x=19
x=19/21
x=19/21
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