(5x-7)/(x+4)=33/12

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Solution for (5x-7)/(x+4)=33/12 equation: 



(5x-7)/(x+4)=33/12

We move all terms to the left:

(5x-7)/(x+4)-(33/12)=0



Domain of the equation: (x+4)!=0

We move all terms containing x to the left, all other terms to the right

x!=-4

x∈R



We add all the numbers together, and all the variables

(5x-7)/(x+4)-(+33/12)=0

We get rid of parentheses

(5x-7)/(x+4)-33/12=0

We calculate fractions


(60x-84)/(12x+48)+(-33x-132)/(12x+48)=0

We multiply all the terms by the denominator


(60x-84)+(-33x-132)=0

We get rid of parentheses

60x-33x-84-132=0

We add all the numbers together, and all the variables

27x-216=0

We move all terms containing x to the left, all other terms to the right

27x=216

x=216/27

x=8

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