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(5x-7)/(x+4)=33/12
We move all terms to the left:
(5x-7)/(x+4)-(33/12)=0
Domain of the equation: (x+4)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x!=-4
x∈R
(5x-7)/(x+4)-(+33/12)=0
We get rid of parentheses
(5x-7)/(x+4)-33/12=0
We calculate fractions
(60x-84)/(12x+48)+(-33x-132)/(12x+48)=0
We multiply all the terms by the denominator
(60x-84)+(-33x-132)=0
We get rid of parentheses
60x-33x-84-132=0
We add all the numbers together, and all the variables
27x-216=0
We move all terms containing x to the left, all other terms to the right
27x=216
x=216/27
x=8
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