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(5x-7)/3x+1=1
We move all terms to the left:
(5x-7)/3x+1-(1)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
(5x-7)/3x=0
We multiply all the terms by the denominator
(5x-7)=0
We get rid of parentheses
5x-7=0
We move all terms containing x to the left, all other terms to the right
5x=7
x=7/5
x=1+2/5
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