(5x-7)/5=(7x+3)/2

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Solution for (5x-7)/5=(7x+3)/2 equation: 



(5x-7)/5=(7x+3)/2

We move all terms to the left:

(5x-7)/5-((7x+3)/2)=0

We calculate fractions


5x/()+(-((7x+3)*5)/()=0



We calculate terms in parentheses: +(-((7x+3)*5)/(), so:

-((7x+3)*5)/(

We multiply all the terms by the denominator


-((7x+3)*5)



We calculate terms in parentheses: -((7x+3)*5), so:

(7x+3)*5

We multiply parentheses

35x+15

Back to the equation:

-(35x+15)



We get rid of parentheses

-35x-15

Back to the equation:

+(-35x-15)



We get rid of parentheses

5x/()-35x-15=0

We multiply all the terms by the denominator


5x-35x*()-15*()=0

We add all the numbers together, and all the variables

5x-35x*()=0

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