(5x-7)/8=(3x+1)/10

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Solution for (5x-7)/8=(3x+1)/10 equation: 



(5x-7)/8=(3x+1)/10

We move all terms to the left:

(5x-7)/8-((3x+1)/10)=0

We calculate fractions


5x/()+(-((3x+1)*8)/()=0



We calculate terms in parentheses: +(-((3x+1)*8)/(), so:

-((3x+1)*8)/(

We multiply all the terms by the denominator


-((3x+1)*8)



We calculate terms in parentheses: -((3x+1)*8), so:

(3x+1)*8

We multiply parentheses

24x+8

Back to the equation:

-(24x+8)



We get rid of parentheses

-24x-8

Back to the equation:

+(-24x-8)



We get rid of parentheses

5x/()-24x-8=0

We multiply all the terms by the denominator


5x-24x*()-8*()=0

We add all the numbers together, and all the variables

5x-24x*()=0

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