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(5x-7)=(4x+15)
We move all terms to the left:
(5x-7)-((4x+15))=0
We get rid of parentheses
5x-((4x+15))-7=0
We calculate terms in parentheses: -((4x+15)), so:We get rid of parentheses
(4x+15)
We get rid of parentheses
4x+15
Back to the equation:
-(4x+15)
5x-4x-15-7=0
We add all the numbers together, and all the variables
x-22=0
We move all terms containing x to the left, all other terms to the right
x=22
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