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(5x-7)=(x+33)
We move all terms to the left:
(5x-7)-((x+33))=0
We get rid of parentheses
5x-((x+33))-7=0
We calculate terms in parentheses: -((x+33)), so:We get rid of parentheses
(x+33)
We get rid of parentheses
x+33
Back to the equation:
-(x+33)
5x-x-33-7=0
We add all the numbers together, and all the variables
4x-40=0
We move all terms containing x to the left, all other terms to the right
4x=40
x=40/4
x=10
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