(5x-8)+(7x-12)=(10x-2)

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Solution for (5x-8)+(7x-12)=(10x-2) equation: 



(5x-8)+(7x-12)=(10x-2)

We move all terms to the left:

(5x-8)+(7x-12)-((10x-2))=0

We get rid of parentheses

5x+7x-((10x-2))-8-12=0



We calculate terms in parentheses: -((10x-2)), so:

(10x-2)

We get rid of parentheses

10x-2

Back to the equation:

-(10x-2)



We add all the numbers together, and all the variables

12x-(10x-2)-20=0

We get rid of parentheses

12x-10x+2-20=0

We add all the numbers together, and all the variables

2x-18=0

We move all terms containing x to the left, all other terms to the right

2x=18

x=18/2

x=9

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