(5x-8)/3=(4x-7)/2

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Solution for (5x-8)/3=(4x-7)/2 equation: 



(5x-8)/3=(4x-7)/2

We move all terms to the left:

(5x-8)/3-((4x-7)/2)=0

We calculate fractions


5x/()+(-((4x-7)*3)/()=0



We calculate terms in parentheses: +(-((4x-7)*3)/(), so:

-((4x-7)*3)/(

We multiply all the terms by the denominator


-((4x-7)*3)



We calculate terms in parentheses: -((4x-7)*3), so:

(4x-7)*3

We multiply parentheses

12x-21

Back to the equation:

-(12x-21)



We get rid of parentheses

-12x+21

Back to the equation:

+(-12x+21)



We get rid of parentheses

5x/()-12x+21=0

We multiply all the terms by the denominator


5x-12x*()+21*()=0

We add all the numbers together, and all the variables

5x-12x*()=0

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