(5x-8)/3=(4x-7)/2

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Solution for (5x-8)/3=(4x-7)/2 equation:



(5x-8)/3=(4x-7)/2
We move all terms to the left:
(5x-8)/3-((4x-7)/2)=0
We calculate fractions
5x/()+(-((4x-7)*3)/()=0
We calculate terms in parentheses: +(-((4x-7)*3)/(), so:
-((4x-7)*3)/(
We multiply all the terms by the denominator
-((4x-7)*3)
We calculate terms in parentheses: -((4x-7)*3), so:
(4x-7)*3
We multiply parentheses
12x-21
Back to the equation:
-(12x-21)
We get rid of parentheses
-12x+21
Back to the equation:
+(-12x+21)
We get rid of parentheses
5x/()-12x+21=0
We multiply all the terms by the denominator
5x-12x*()+21*()=0
We add all the numbers together, and all the variables
5x-12x*()=0

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