(5x-8)/7=(11x-9)/5

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Solution for (5x-8)/7=(11x-9)/5 equation: 



(5x-8)/7=(11x-9)/5

We move all terms to the left:

(5x-8)/7-((11x-9)/5)=0

We calculate fractions


5x/()+(-((11x-9)*7)/()=0



We calculate terms in parentheses: +(-((11x-9)*7)/(), so:

-((11x-9)*7)/(

We multiply all the terms by the denominator


-((11x-9)*7)



We calculate terms in parentheses: -((11x-9)*7), so:

(11x-9)*7

We multiply parentheses

77x-63

Back to the equation:

-(77x-63)



We get rid of parentheses

-77x+63

Back to the equation:

+(-77x+63)



We get rid of parentheses

5x/()-77x+63=0

We multiply all the terms by the denominator


5x-77x*()+63*()=0

We add all the numbers together, and all the variables

5x-77x*()=0

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