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(5x-9)(6x+5)=0
We multiply parentheses ..
(+30x^2+25x-54x-45)=0
We get rid of parentheses
30x^2+25x-54x-45=0
We add all the numbers together, and all the variables
30x^2-29x-45=0
a = 30; b = -29; c = -45;
Δ = b2-4ac
Δ = -292-4·30·(-45)
Δ = 6241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6241}=79$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-79}{2*30}=\frac{-50}{60} =-5/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+79}{2*30}=\frac{108}{60} =1+4/5 $
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