(5x-9)(8x+7)=0

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Solution for (5x-9)(8x+7)=0 equation:



(5x-9)(8x+7)=0
We multiply parentheses ..
(+40x^2+35x-72x-63)=0
We get rid of parentheses
40x^2+35x-72x-63=0
We add all the numbers together, and all the variables
40x^2-37x-63=0
a = 40; b = -37; c = -63;
Δ = b2-4ac
Δ = -372-4·40·(-63)
Δ = 11449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11449}=107$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-107}{2*40}=\frac{-70}{80} =-7/8 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+107}{2*40}=\frac{144}{80} =1+4/5 $

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