(5x-9)/7=(x-6)/(6)+3

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Solution for (5x-9)/7=(x-6)/(6)+3 equation: 



(5x-9)/7=(x-6)/(6)+3

We move all terms to the left:

(5x-9)/7-((x-6)/(6)+3)=0

We calculate fractions


(30x-54)/()+(-((x-6)*7)/()=0



We calculate terms in parentheses: +(-((x-6)*7)/(), so:

-((x-6)*7)/(

We multiply all the terms by the denominator


-((x-6)*7)



We calculate terms in parentheses: -((x-6)*7), so:

(x-6)*7

We multiply parentheses

7x-42

Back to the equation:

-(7x-42)



We get rid of parentheses

-7x+42

Back to the equation:

+(-7x+42)



We get rid of parentheses

(30x-54)/()-7x+42=0

We multiply all the terms by the denominator


(30x-54)-7x*()+42*()=0

We add all the numbers together, and all the variables

(30x-54)-7x*()=0

We get rid of parentheses

30x-7x*()-54=0

We move all terms containing x to the left, all other terms to the right

30x-7x*()=54

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