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(5x-9)/9)+(9x-2)3)=9
We move all terms to the left:
(5x-9)/9)+(9x-2)3)-(9)=0
Domain of the equation: 9)+(9x!=0We add all the numbers together, and all the variables
x∈R
(5x-9)/9)+(9x=0
We multiply all the terms by the denominator
(5x-9)=0
We get rid of parentheses
5x-9=0
We move all terms containing x to the left, all other terms to the right
5x=9
x=9/5
x=1+4/5
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