(5x.5+3)/5=(7-2x.5)/3

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Solution for (5x.5+3)/5=(7-2x.5)/3 equation: 



(5x.5+3)/5=(7-2x.5)/3

We move all terms to the left:

(5x.5+3)/5-((7-2x.5)/3)=0

We add all the numbers together, and all the variables

(5x.5+3)/5-((-2x.5+7)/3)=0

We calculate fractions


(5x.5)/()+(-((-2x.5+7)*5)/()=0



We calculate terms in parentheses: +(-((-2x.5+7)*5)/(), so:

-((-2x.5+7)*5)/(

We multiply all the terms by the denominator


-((-2x.5+7)*5)



We calculate terms in parentheses: -((-2x.5+7)*5), so:

(-2x.5+7)*5

We multiply parentheses

-10x+35

Back to the equation:

-(-10x+35)



We get rid of parentheses

10x-35

Back to the equation:

+(10x-35)



We add all the numbers together, and all the variables

(+5x.5)/()+(10x-35)=0

We get rid of parentheses

(+5x.5)/()+10x-35=0

We multiply all the terms by the denominator


(+5x.5)+10x*()-35*()=0

We add all the numbers together, and all the variables

(+5x.5)+10x*()=0

We get rid of parentheses

5x.5+10x*()=0

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