(5x/20)-(4x/20)=(9/4)

Solution for (5x/20)-(4x/20)=(9/4) equation:

(5x/20)-(4x/20)=(9/4)

We move all terms to the left:

(5x/20)-(4x/20)-((9/4))=0

We add all the numbers together, and all the variables

(+5x/20)-(+4x/20)-((+9/4))=0

We get rid of parentheses

5x/20-4x/20-((+9/4))=0

We calculate fractions


(-16x^2+5x)/()+()/()=0

We add all the numbers together, and all the variables

(-16x^2+5x)/()+1=0

We multiply all the terms by the denominator


(-16x^2+5x)+1*()=0

We add all the numbers together, and all the variables

(-16x^2+5x)=0

We get rid of parentheses

-16x^2+5x=0

a = -16; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-16)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-16}=\frac{-10}{-32}
=5/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-16}=\frac{0}{-32}
=0
$